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3x^2=361
We move all terms to the left:
3x^2-(361)=0
a = 3; b = 0; c = -361;
Δ = b2-4ac
Δ = 02-4·3·(-361)
Δ = 4332
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{4332}=\sqrt{1444*3}=\sqrt{1444}*\sqrt{3}=38\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-38\sqrt{3}}{2*3}=\frac{0-38\sqrt{3}}{6} =-\frac{38\sqrt{3}}{6} =-\frac{19\sqrt{3}}{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+38\sqrt{3}}{2*3}=\frac{0+38\sqrt{3}}{6} =\frac{38\sqrt{3}}{6} =\frac{19\sqrt{3}}{3} $
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